Optimal. Leaf size=151 \[ \frac {565 \sqrt {1-2 x} \sqrt {5 x+3}}{2744 (3 x+2)}-\frac {5 \sqrt {1-2 x} \sqrt {5 x+3}}{196 (3 x+2)^2}-\frac {\sqrt {1-2 x} \sqrt {5 x+3}}{7 (3 x+2)^3}+\frac {2 \sqrt {5 x+3}}{7 \sqrt {1-2 x} (3 x+2)^3}-\frac {7435 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{2744 \sqrt {7}} \]
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Rubi [A] time = 0.05, antiderivative size = 151, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {99, 151, 12, 93, 204} \begin {gather*} \frac {565 \sqrt {1-2 x} \sqrt {5 x+3}}{2744 (3 x+2)}-\frac {5 \sqrt {1-2 x} \sqrt {5 x+3}}{196 (3 x+2)^2}-\frac {\sqrt {1-2 x} \sqrt {5 x+3}}{7 (3 x+2)^3}+\frac {2 \sqrt {5 x+3}}{7 \sqrt {1-2 x} (3 x+2)^3}-\frac {7435 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{2744 \sqrt {7}} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 93
Rule 99
Rule 151
Rule 204
Rubi steps
\begin {align*} \int \frac {\sqrt {3+5 x}}{(1-2 x)^{3/2} (2+3 x)^4} \, dx &=\frac {2 \sqrt {3+5 x}}{7 \sqrt {1-2 x} (2+3 x)^3}-\frac {2}{7} \int \frac {-\frac {53}{2}-45 x}{\sqrt {1-2 x} (2+3 x)^4 \sqrt {3+5 x}} \, dx\\ &=\frac {2 \sqrt {3+5 x}}{7 \sqrt {1-2 x} (2+3 x)^3}-\frac {\sqrt {1-2 x} \sqrt {3+5 x}}{7 (2+3 x)^3}-\frac {2}{147} \int \frac {-\frac {525}{4}-210 x}{\sqrt {1-2 x} (2+3 x)^3 \sqrt {3+5 x}} \, dx\\ &=\frac {2 \sqrt {3+5 x}}{7 \sqrt {1-2 x} (2+3 x)^3}-\frac {\sqrt {1-2 x} \sqrt {3+5 x}}{7 (2+3 x)^3}-\frac {5 \sqrt {1-2 x} \sqrt {3+5 x}}{196 (2+3 x)^2}-\frac {\int \frac {-\frac {5355}{8}-\frac {525 x}{2}}{\sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}} \, dx}{1029}\\ &=\frac {2 \sqrt {3+5 x}}{7 \sqrt {1-2 x} (2+3 x)^3}-\frac {\sqrt {1-2 x} \sqrt {3+5 x}}{7 (2+3 x)^3}-\frac {5 \sqrt {1-2 x} \sqrt {3+5 x}}{196 (2+3 x)^2}+\frac {565 \sqrt {1-2 x} \sqrt {3+5 x}}{2744 (2+3 x)}-\frac {\int -\frac {156135}{16 \sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx}{7203}\\ &=\frac {2 \sqrt {3+5 x}}{7 \sqrt {1-2 x} (2+3 x)^3}-\frac {\sqrt {1-2 x} \sqrt {3+5 x}}{7 (2+3 x)^3}-\frac {5 \sqrt {1-2 x} \sqrt {3+5 x}}{196 (2+3 x)^2}+\frac {565 \sqrt {1-2 x} \sqrt {3+5 x}}{2744 (2+3 x)}+\frac {7435 \int \frac {1}{\sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx}{5488}\\ &=\frac {2 \sqrt {3+5 x}}{7 \sqrt {1-2 x} (2+3 x)^3}-\frac {\sqrt {1-2 x} \sqrt {3+5 x}}{7 (2+3 x)^3}-\frac {5 \sqrt {1-2 x} \sqrt {3+5 x}}{196 (2+3 x)^2}+\frac {565 \sqrt {1-2 x} \sqrt {3+5 x}}{2744 (2+3 x)}+\frac {7435 \operatorname {Subst}\left (\int \frac {1}{-7-x^2} \, dx,x,\frac {\sqrt {1-2 x}}{\sqrt {3+5 x}}\right )}{2744}\\ &=\frac {2 \sqrt {3+5 x}}{7 \sqrt {1-2 x} (2+3 x)^3}-\frac {\sqrt {1-2 x} \sqrt {3+5 x}}{7 (2+3 x)^3}-\frac {5 \sqrt {1-2 x} \sqrt {3+5 x}}{196 (2+3 x)^2}+\frac {565 \sqrt {1-2 x} \sqrt {3+5 x}}{2744 (2+3 x)}-\frac {7435 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{2744 \sqrt {7}}\\ \end {align*}
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Mathematica [A] time = 0.06, size = 90, normalized size = 0.60 \begin {gather*} \frac {7 \sqrt {5 x+3} \left (-10170 x^3-8055 x^2+3114 x+2512\right )-7435 \sqrt {7-14 x} (3 x+2)^3 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{19208 \sqrt {1-2 x} (3 x+2)^3} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.25, size = 122, normalized size = 0.81 \begin {gather*} \frac {\sqrt {5 x+3} \left (-\frac {7435 (1-2 x)^3}{(5 x+3)^3}+\frac {89880 (1-2 x)^2}{(5 x+3)^2}+\frac {323547 (1-2 x)}{5 x+3}+6272\right )}{2744 \sqrt {1-2 x} \left (\frac {1-2 x}{5 x+3}+7\right )^3}-\frac {7435 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{2744 \sqrt {7}} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.00, size = 116, normalized size = 0.77 \begin {gather*} -\frac {7435 \, \sqrt {7} {\left (54 \, x^{4} + 81 \, x^{3} + 18 \, x^{2} - 20 \, x - 8\right )} \arctan \left (\frac {\sqrt {7} {\left (37 \, x + 20\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{14 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) - 14 \, {\left (10170 \, x^{3} + 8055 \, x^{2} - 3114 \, x - 2512\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{38416 \, {\left (54 \, x^{4} + 81 \, x^{3} + 18 \, x^{2} - 20 \, x - 8\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 3.05, size = 336, normalized size = 2.23 \begin {gather*} \frac {1487}{76832} \, \sqrt {70} \sqrt {10} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {70} \sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} - \frac {16 \, \sqrt {5} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}}{12005 \, {\left (2 \, x - 1\right )}} - \frac {99 \, \sqrt {10} {\left (527 \, {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{5} - 253120 \, {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{3} - \frac {36299200 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}{\sqrt {5 \, x + 3}} + \frac {145196800 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}}{9604 \, {\left ({\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{2} + 280\right )}^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.02, size = 257, normalized size = 1.70 \begin {gather*} \frac {\left (401490 \sqrt {7}\, x^{4} \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+602235 \sqrt {7}\, x^{3} \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+142380 \sqrt {-10 x^{2}-x +3}\, x^{3}+133830 \sqrt {7}\, x^{2} \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+112770 \sqrt {-10 x^{2}-x +3}\, x^{2}-148700 \sqrt {7}\, x \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )-43596 \sqrt {-10 x^{2}-x +3}\, x -59480 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )-35168 \sqrt {-10 x^{2}-x +3}\right ) \sqrt {-2 x +1}\, \sqrt {5 x +3}}{38416 \left (3 x +2\right )^{3} \left (2 x -1\right ) \sqrt {-10 x^{2}-x +3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.23, size = 211, normalized size = 1.40 \begin {gather*} \frac {7435}{38416} \, \sqrt {7} \arcsin \left (\frac {37 \, x}{11 \, {\left | 3 \, x + 2 \right |}} + \frac {20}{11 \, {\left | 3 \, x + 2 \right |}}\right ) - \frac {2825 \, x}{4116 \, \sqrt {-10 \, x^{2} - x + 3}} + \frac {1145}{2744 \, \sqrt {-10 \, x^{2} - x + 3}} + \frac {1}{63 \, {\left (27 \, \sqrt {-10 \, x^{2} - x + 3} x^{3} + 54 \, \sqrt {-10 \, x^{2} - x + 3} x^{2} + 36 \, \sqrt {-10 \, x^{2} - x + 3} x + 8 \, \sqrt {-10 \, x^{2} - x + 3}\right )}} - \frac {23}{252 \, {\left (9 \, \sqrt {-10 \, x^{2} - x + 3} x^{2} + 12 \, \sqrt {-10 \, x^{2} - x + 3} x + 4 \, \sqrt {-10 \, x^{2} - x + 3}\right )}} - \frac {125}{1176 \, {\left (3 \, \sqrt {-10 \, x^{2} - x + 3} x + 2 \, \sqrt {-10 \, x^{2} - x + 3}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\sqrt {5\,x+3}}{{\left (1-2\,x\right )}^{3/2}\,{\left (3\,x+2\right )}^4} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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